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IB Biology · Theme B: Form and function · SL and HL

B1.2 Proteins

A one-page summary of B1.2 Proteins, the key terms to know, and sample exam questions with answers. For the full lesson, open the illustrated revision slides or practise in the app.

Open the B1.2 revision slides Practise B1.2 in the app

Guiding questions

What is the relationship between amino acid sequence and the diversity in form and function of proteins?

How are protein molecules affected by their chemical and physical environments?

What B1.2 covers

Amino acids and the polypeptide chain

Structure and function: from R-group to whole protein

B1.2 Proteins: summary

Amino acids & peptide bonds

  • Backbone: amino + carboxyl + H + R-group on one alpha carbon.
  • Condensation joins amino acids (releases water); hydrolysis breaks them apart.

Diet & sequence variety

  • Essential amino acids must come from food; vegan diets need mixed plant sources.
  • 20 amino acids → 20ⁿ possible sequences; order and length set the protein.

Denaturation (SL)

  • Heat or pH unfolds the protein; weak interactions break.
  • Peptide bonds stay intact — denaturation is not hydrolysis.

Primary & secondary HL

  • Primary sequence determines the fold (sickle cell: Glu→Val).
  • Secondary: α-helix and β-sheet held by backbone C=O···N–H hydrogen bonds.

Tertiary structure HL

  • R-group interactions: hydrogen, ionic, disulfide bridges, hydrophobic core.
  • Polarity places hydrophobic groups inside, hydrophilic groups outside.

Quaternary & form HL

  • Subunits: insulin (non-conjugated), haemoglobin (conjugated, haem).
  • Globular (soluble, dynamic) vs fibrous (insoluble, structural).

Key terms

Amino acid
Molecule with an alpha carbon bonded to an amino group, a carboxyl group, an H and an R-group.
Peptide bond
Covalent C–N bond between amino acids, formed by condensation.
Polypeptide
A chain of many amino acids linked by peptide bonds.
Essential amino acid
An amino acid the body cannot synthesise; it must come from the diet.
Denaturation
Loss of 3D shape without breaking peptide bonds; caused by heat or pH.
Primary structure HL
The linear amino acid sequence of a polypeptide.
Secondary structure HL
α-helix and β-pleated sheet, held by backbone hydrogen bonds.
Tertiary structure HL
Overall 3D fold of one chain, held by R-group interactions.
Quaternary structure HL
Assembly of two or more polypeptide chains into one protein.
Conjugated protein HL
Protein with a non-protein prosthetic group, e.g. haem in haemoglobin.

Sample exam questions

Three of the 36 multiple-choice questions for B1.2. Try each one before opening the answer.

Question 1. Valine and lysine are essential amino acids. Alanine and glycine are non-essential amino acids. What is a valid conclusion for one of these amino acids?

  1. Lysine is synthesised by the human body
  2. Valine must be supplied in the diet
  3. Alanine can only be obtained from food
  4. Glycine is not used in the human body
Show the answer

Answer: B. Valine is an essential amino acid: human cells cannot synthesise it, so it must be obtained from the diet. Lysine is also essential (not synthesised by the body), while alanine and glycine are non-essential — the body can synthesise them from other molecules, though it can still use dietary sources too.

Question 2. Insulin is a protein made of two polypeptide chains with a total of 51 amino acids. How many peptide bonds are there in a molecule of human insulin?

  1. 48
  2. 49
  3. 50
  4. 51
Show the answer

Answer: B. Each polypeptide chain has one fewer peptide bond than it has amino acids (a chain of n amino acids has n−1 peptide bonds, since a peptide bond only forms between adjacent residues). Insulin's two chains are 21 and 30 amino acids long, giving 20 + 29 = 49 peptide bonds — NOT 51−1=50, because the count must be done separately for each chain, not for the combined total.

Question 3. The R groups (side chains) of amino acids determine their chemical properties. Which category of amino acids would you expect to find buried in the interior of a soluble globular protein?

  1. Hydrophobic (nonpolar) amino acids, because they avoid contact with the aqueous environment
  2. Positively charged amino acids, because they are attracted to the negatively charged DNA
  3. All amino acids are distributed randomly throughout the protein
  4. Hydrophilic (polar) amino acids, because they interact favourably with water
Show the answer

Answer: A. In an aqueous environment, protein folding buries hydrophobic (nonpolar) R groups in the interior, away from water, and exposes hydrophilic (polar and charged) R groups on the surface where they can interact with water. This hydrophobic core is a major driving force for protein folding.

Linking questions

Questions that connect B1.2 to other parts of the course, the kind that come up in Paper 2.

Practise B1.2

36 quiz questions9 data questions5 exam questionsmarkschemes included

Study notes, every question and full markschemes for B1.2 are in the app with Pro. Two lessons are completely free to try: A1.1 Water and B1.1 Carbohydrates and lipids.

Practise B1.2 in the app Revision slides